Final answer to the problem
$x=0+2\pi n,\:x=\pi+2\pi n,\:x=\frac{1}{2}\pi+2\pi n\:,\:\:n\in\Z$
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1
Simplify by applying the identity: $\sec\left(\theta \right)^2-\tan\left(\theta \right)^2 = 1$
$\sqrt{1-\cos\left(x\right)^2}=\sin\left(x\right)^2$
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$\sqrt{1-\cos\left(x\right)^2}=\sin\left(x\right)^2$
Learn how to solve trigonometric equations problems step by step online. Solve the trigonometric equation (sec(x)^2-tan(x)^2-cos(x)^2)^(1/2)=sin(x)^2. Simplify by applying the identity: \sec\left(\theta \right)^2-\tan\left(\theta \right)^2 = 1. Apply the trigonometric identity: 1-\cos\left(\theta \right)^2=\sin\left(\theta \right)^2. Cancel exponents 2 and 1. Grouping all terms to the left side of the equation.
Final answer to the problem
$x=0+2\pi n,\:x=\pi+2\pi n,\:x=\frac{1}{2}\pi+2\pi n\:,\:\:n\in\Z$
